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$(X){{C}_{4}}{{H}_{7}}OCl\xrightarrow{N{{H}_{3}}}{{C}_{4}}{{H}_{9}}ON\xrightarrow[KOH]{B{{r}_{2}}}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}};$ Compound $(X)$ is
$RN{H_2}$ reacts with ${C_6}{H_5}S{O_2}Cl$ in aqueous $KOH$ to give a clear solution. On acidification a precipitate is obtained which is due to the formation of