- A$NaB{H_4}$
- B${H_2} - Pd/C$
- C$LiAl{H_4}$
- ✓$Zn - Hg/HCl$
This reaction is known as Clemmenson reduction.
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[Given: Freezing point of ethanol is $156.0 K$ Density of ethanol is $0.80\,g\,cm ^{-3}$.
Freezing point depression constant of ethanol is $\left.2.00\,K\,kg\,mol\,m ^{-1}\right]$
Reason : Oxidation state of $Cr$ in $Na_2CrO_4$ is $+VI$
$C{H_3}C{H_2}OH\xrightarrow{{P + {I_2}}}A\xrightarrow[{Ether}]{{Mg}}B $ $\xrightarrow{{HCHO}}C\xrightarrow{{{H_2}O}}D,$
then compound $'D'$ is -
$\mathrm{x}=$ . . . . . . . . . (Nearest integer)
Given : $\left(\mathrm{K}_{\mathrm{r}}\right)_{\text {water }}=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$.
density of acetic acid is $1.2 \mathrm{~g} \mathrm{~mol}^{-1}$
molar mass of water $=18 \mathrm{~g} \mathrm{~mol}^{-1}$.
molar mass of acetic acid $=60 \mathrm{~g} \mathrm{~mol}^{-1}$.
density of water $=1 \mathrm{~g} \mathrm{~cm}^{-3}$
Acetic acid dissociates as
$\mathrm{CH}_3 \mathrm{COOH} \rightleftharpoons \mathrm{CH}_3 \mathrm{COO}^{\oplus}+\mathrm{H}^{\oplus}$