(આપેલ $CaF _{2}$ નું મોલર દળ = $78 \,g mol ^{-1}$ )
$S =\frac{2.34 \times 10^{-3}}{0.1 \times 78}=\frac{2.34}{78} \times 10^{-2}=3 \times 10^{-4}\,mol / L$
$K _{ sp }\left( CaF _{2}\right)=4 S ^{3}=4\left(3 \times 10^{-4}\right)^{3}$
$=108 \times 10^{-12}$
$=0.0108 \times 10^{-8}( mol / L )^{3}$