Question
Calculate $pH$ and $pOH$ of $0.02 \text{M HCl}$ .
✓
Answer
Given : $C =6.02 M HCl ; pH =? pOH =$ ?
$HCl _{( aq )} \longrightarrow H _{( aq )}^{+}+ Cl _{( aq )}^{-}$
$0.02 M $
${\left[ H ^{+}\right]=\left[ H _3 O ^{+}\right]=0.02 M }$
$PH =-\log _{10}\left[ H _3 O ^{+}\right]$
$=-\log _{10} 0.02$
$=-(\overline{2}.3010)$
$=2-0.3010=1.699$
$pH + pOH =14$
$\therefore pOH =14- pH$
$=14-1.699$
$=12.3010$
$pH =1.6990 ; pOH =12.3010$.
$HCl _{( aq )} \longrightarrow H _{( aq )}^{+}+ Cl _{( aq )}^{-}$
$0.02 M $
${\left[ H ^{+}\right]=\left[ H _3 O ^{+}\right]=0.02 M }$
$PH =-\log _{10}\left[ H _3 O ^{+}\right]$
$=-\log _{10} 0.02$
$=-(\overline{2}.3010)$
$=2-0.3010=1.699$
$pH + pOH =14$
$\therefore pOH =14- pH$
$=14-1.699$
$=12.3010$
$pH =1.6990 ; pOH =12.3010$.
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