Question
Calculate the coefficient of correlation from the following data:$\text{Cov.}(\text{X,Y})=488,\sigma_\text{x}=28.70,\sigma_\text{y}=18.2\text{N}=10$

Answer

$\text{r}=\frac{\text{Cov. (X,Y)}}{\sqrt{\text{Var. (X)}}\sqrt{\text{Var. (Y)}}}$$=\frac{488}{\sqrt{823.69}\sqrt{324.72}}$
$=\frac{488}{28.70\times18.01}=\frac{488}{516.8}=0.94$
High degree of correlation prevails between X and Y.

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