Question
Calculate the efficiency of a Carnot's engine working between steam point and ice point.

Answer

Here, steam point,
$\text{T}_1=100\ ^\circ\text{C}$
$=100+273=373\text{K}$
Ice point , $\text{T}_2=0^\circ{\text{C}}$
$=0+273=273\text{K}$
As $\eta=1-\frac{\text{T}_2}{\text{T}_1}$
$\therefore\ \eta=1-\frac{273}{373}=\frac{100}{373}$
$=\frac{100}{373}\times100\%$
$=26.81\%$

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