Question
Calculate the electron gain enthalpy of fluorine from the data given below: $\Delta_{\mathrm{f}} \mathrm{H}^{\circ}$ of $\mathrm{KF}=-560.8 \mathrm{~kJ} \mathrm{~mol}{ }^{-1}$, Sublimation energy of $\mathrm{K}=87.8 \mathrm{~kJ} \mathrm{~mol}^{-1}$, Dissociation energy of F , is $158.9 \mathrm{~kJ} \mathrm{~mol}{ }^{-1}$, Lattice energy of $\mathrm{KF}^{-15}-807.5 \mathrm{~kJ} \mathrm{~mol}{ }^{-1}$ and Ionisation energy of K is $414.2 \mathrm{~kJ} \mathrm{~mol}^{-1}$.

Answer

Electron gain enthalpy $=\Delta_\text{f}\text{H}-\text{S}-\frac{1}{2}\text{D}-\text{I.E.}-\text{U}$ 'S' is sublimation energy; 'D' is bond dissociation enthalpy. I.E. is ionisation elthalpy. 'U' represents lattice energy.$\text{E.G.E.}=-560.8-87.8-\frac{1}{2}\\\times158.9-414.2-(-807.5)$
$\text{E.G.E.}=-1142.25+807.5\\=-334.75\text{kJ mol}^{-1}$

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