MCQ
Calculate the enthalpy change for the reaction
$H_2 + F_2 \longrightarrow 2HF$
given that
Bond energy of $H-H$ bond $= 434\, kJ/mol$
Bond energy of $F-F$ bond $= 158\, kJ/mol$
Bond energy of $H-F$ bond $= 565\, kJ/mol$
.....$ kJ$
- A$538$
- ✓$-538$
- C$27$
- D$-27$