$(C-H= 414; H-O = 463; H-Cl=431;$$ C-Cl=326, C-O=335)$
$CH_3-OH(g) + HCl(g) \rightarrow CH_3-Cl(g) + H_2O(g)$
$=[3 \times \mathrm{B} \cdot \mathrm{E}(\mathrm{CH})+1 \times \mathrm{B} \cdot \mathrm{E}(\mathrm{OH})+1 \times \mathrm{B} \cdot \mathrm{E}(\mathrm{C}-\mathrm{O})+1 \times \mathrm{B} \cdot \mathrm{E}(\mathrm{HCl})] $
$-[3 \times \mathrm{B} \cdot \mathrm{E}(\mathrm{CH})+1 \times \mathrm{B} \cdot \mathrm{E}(\mathrm{C}-\mathrm{Cl})+2 \times \mathrm{B} \cdot \mathrm{E}(\mathrm{OH})] $
$=-23\, \mathrm{kJ} / \mathrm{mol} $
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