MCQ
Calculate the final temperature of a monoatomic ideal gas that is compressed reversibly and adiabatically from $16\, L$ to $2\, L$ at $300\, K$? ......$K$
- A$600$
- B$1044.6\, $
- ✓$1200\, $
- D$2400\, $
✓
Answer
Correct option: C.
$1200\, $
c
$T_{1} V_{1}^{\gamma-1}=T_{2} V_{2}^{\gamma-1}$
$T_{1} V_{1}^{\gamma-1}=T_{2} V_{2}^{\gamma-1}$
$\mathrm{T}_{1}=300 \quad \mathrm{T}_{2}=?$
$V_{1}=16 \quad V_{2}=2 \,L$
$\gamma=\frac{5}{3} \quad \frac{300}{T_{2}}=(8)^{2 / 3}$
$\mathrm{T}_{2}=1200 \,\mathrm{K}$
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