Question
Calculate the oxidation number of underlinesd element in the following: $\text{Na}_2\text{B}_4,\text{O}_\text{S}\text{O}_4$
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Answer
$\text{Na}_2\text{B}_4\text{O}_7;$
$+2+4\text{x}-14$
$4\text{x}=12$
$\text{x}=-3$
$\text{O}_\text{S}\text{O}_4$
$\text{x}-8=0$
$\text{x}=+8$
$+2+4\text{x}-14$
$4\text{x}=12$
$\text{x}=-3$
$\text{O}_\text{S}\text{O}_4$
$\text{x}-8=0$
$\text{x}=+8$
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