$CaC{O_3}\left( s \right)\overset \Delta \longleftrightarrow CaO\left( s \right) + C{O_2} \uparrow ,{K_p} = 8 \times {10^{ - 2}}$
$C{O_2}\left( g \right) + C\left( s \right) \rightleftharpoons 2CO\left( g \right),{K_p} = 2$
$\mathrm{K}_{\mathrm{p}}$ will be due to $\mathrm{CO}_{2}(\mathrm{g})$
So, $\left[\mathrm{P}_{\mathrm{CO}_{2}}\right]=8 \times 10^{-2}$
$\mathrm{CO}_{2}(\mathrm{g})+\mathrm{C}(\mathrm{s}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}), \mathrm{K}_{\mathrm{p}}=2$
$\mathrm{K}_{\mathrm{p}}=\frac{\left[\mathrm{P}_{\mathrm{CO}}\right]^{2}}{\left[\mathrm{P}_{\mathrm{CO}_{2}}\right]} \quad \mathrm{K}_{\mathrm{P}}=\frac{\left[\mathrm{P}_{\mathrm{CO}}\right]^{2}}{0.08}=2$
$\left[\mathrm{P}_{\mathrm{CO}}\right]^{2}=2 \times 0.08 \quad[\mathrm{PCO}]=\sqrt{0.16}=0.4$
Partial press. of $\mathrm{CO}=0.4$
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