Question
Calculate the solid angle subtended by the periphery of an area of $1cm^2$ at a point situated symmetrically at a distance of 5cm from the area.

Answer

Solid angle, $\Omega=\frac{\text{Area}}{(\text{Radial distance})^2}$$=\frac{1\text{cm}^2}{(5\text{cm})^2}=\frac{1}{25}=4\times10^{-2}\ \text{steradian}$
($\because$ Area = $1cm^2$, distance = $5cm$)

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free