Question
If the sum and difference of two vector $\vec{A}$ and $\vec{B}$ are perpendicular to each other then prove that two vectors are equal in magnitude.

Answer

Sum of two vectors $\vec{A}$ and $\vec{B}=\vec{A}+\vec{B}$
$\text { Difference }=\vec{A}-\vec{B}$
$\because$ It is given that both are perpendicular hence their scalar product will be zero.
$\begin{aligned}
(\vec{A}+\vec{B}) \cdot(\vec{A}-\vec{B}) & =0 \\
\text { or } \quad \vec{A} \cdot \vec{A}-\vec{A} \cdot \vec{B}+\vec{B} \cdot \vec{A}-\vec{B} \cdot \vec{B} & =0
\end{aligned}$
We know that $\vec{A} \cdot \vec{B}=\vec{B} \cdot \vec{A}$
$\begin{aligned}
A^2-B^2 & =0 \\
A & =B
\end{aligned}$
Hence, both vectors are equal in magnitude.

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