MCQ
Calculate the work done, if a wire is loaded by $'Mg'$ weight and the increase in length is $'l'$
- A$Mgl$
- B$Zero$
- ✓$Mgl/2$
- D$2Mgl$
✓
Answer
Correct option: C.
$Mgl/2$
c
(c) Work done $=$ $\frac{1}{2}Fl = \frac{{Mgl}}{2}$
(c) Work done $=$ $\frac{1}{2}Fl = \frac{{Mgl}}{2}$
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