Question
Calculate the work done when:
A $5 \ kg$ weight is lifted $10 \ m$ vertically. $(g = 9.8 m/s^2)$

Answer

Force $= m \times g = 5 \times 9.8 = 49 N$; Distance $= 10 m$
$\therefore $ Work done $= F \times d = 49 \times 10 = 490 J.$

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