MCQ
Carbon is in the lowest oxidation state in
- ✓$C{H_4}$
- B$CC{l_4}$
- C$C{F_4}$
- D$C{O_2}$
✓
Answer
Correct option: A.
$C{H_4}$
(a) In $ (b, c, d)$ carbon show $+ 4 $ oxidation state while in $(a)$ carbon show $-4$ oxidation state.
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Similar questions
Match List $I$ with List $II$
→|
List $-I$ (Element) |
List $-II$ (Electronic Configuration) | ||
| $A.$ | $N$ | $I.$ | $[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^5$ |
| $B.$ | $S$ | $II.$ | $[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^4$ |
| $C.$ | $Br$ | $III.$ | $[\mathrm{He}] 2 \mathrm{~s}^2 2 \mathrm{p}^3$ |
| $D.$ | $Kr$ | $IV.$ | $[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^6$ |
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