Question
$\ce{IUPAC}$ name of $\ce{Na_3[Co(ONO)_{6}]}$ is$:$
✓
Answer
The above complex $\ce{Na_3[Co(ONO)_6]}$ has two ions: $Na+$ and a complex ion which is negatively charged $\ce{[Co(ONO)_6]^{3−}}$
According to the rules, name of the positive ion comes first $($i.e., sodium$),$ do not mention the number of sodium as it is not present in a square bracket.
After naming the positive ion, next will be the negative ion,
Now in this example, the negative ion is a complex compound, which contain's 'metal' and 'ligand'.
While naming a complex, name of ligand comes first, also mention the number of ligand by using prefix $($di, tri, tetra. etc..$)$ and if a bidentate ligand is present then mention the atom which is attached to central metal $($i.e., hexanitrito $−O−)$ followed by name of metal with the ending 'ate' $($i.e., cobaltate, always use the word 'ate' if the complex is negatively charge$)$ and than oxidation number of metal.
To show the oxidation state, we use Roman numerals inside parenthesis.
According to the rules, name of the positive ion comes first $($i.e., sodium$),$ do not mention the number of sodium as it is not present in a square bracket.
After naming the positive ion, next will be the negative ion,
Now in this example, the negative ion is a complex compound, which contain's 'metal' and 'ligand'.
While naming a complex, name of ligand comes first, also mention the number of ligand by using prefix $($di, tri, tetra. etc..$)$ and if a bidentate ligand is present then mention the atom which is attached to central metal $($i.e., hexanitrito $−O−)$ followed by name of metal with the ending 'ate' $($i.e., cobaltate, always use the word 'ate' if the complex is negatively charge$)$ and than oxidation number of metal.
To show the oxidation state, we use Roman numerals inside parenthesis.
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