Question
$\ce{[Ti(H_2O)]^{3+}}$ is coloured while $\ce{[Sc(H_2O)_6]^{3+}}$ is colourless.

Answer

This is due to $d-d$ transition of electron in $\ce{[Ti(H_2O)]^{3+}}$ complex $\ce{Ti^{3+}}$ has one electron in $d-$orbital $(3d^1)$ which absorb energy corresponding to blue$-$green region and jumps from $t_{2g}$ to $e_g$ set of $d-$orbitals $\big(\text{t}^1_{2\text{g}}\text{ e}^0_{\text{g}}\xrightarrow{\ \ \ \ \ }\text{t}^0_{2\text{g}}\text{ e}^1_{\text{g}}\big).$ But $Sc^{3+}$ has no electron in the $d-$orbital.

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