$CH _{3}- C \equiv CH \stackrel{2 HBr }{\longrightarrow} \stackrel{ H _{2} O }{\longrightarrow}$ નીપજ, નીપજ કઈ છે:

Question

A$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}} \\
{|\,\,\,\,} \\
{\,OH}
\end{array}$
B$\begin{array}{*{20}{c}}
{C{H_3} - C - C{H_3}} \\
{\,\,\,||\,\,\,\,} \\
{\,\,\,O\,\,\,\,}
\end{array}$
C$\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - C - H} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,}
\end{array}$
D$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2}} \\
{\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,\,\,\,\,\,\,\,OH}
\end{array}$

AIIMS 2019, Medium

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Solution

b
The complete reaction is shown below.

$C{H_3} - C = CH\xrightarrow{{2HBr}}\mathop {\begin{array}{*{20}{c}}
{Br} \\
| \\
{C{H_3} - C - C{H_3}} \\
| \\
{Br}
\end{array}}\limits_{(A)} \xrightarrow{{{H_2}O}}$

$\begin{array}{*{20}{c}}
{\,\,\,\,OH} \\
| \\
{C{H_3} - C - C{H_3}} \\
| \\
{\,\,\,\,\,OH}
\end{array}\xrightarrow[{ - {H_2}O}]{}\mathop {\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}}\limits_{(B)} $

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