MCQ
$CH _{3}- C \equiv CH \stackrel{2 HBr }{\longrightarrow} \stackrel{ H _{2} O }{\longrightarrow}$ Product, Product is: 
  • A
    $\begin{array}{*{20}{c}}
      {C{H_3} - CH - C{H_3}} \\ 
      {|\,\,\,\,} \\ 
      {\,OH} 
    \end{array}$
  • $\begin{array}{*{20}{c}}
      {C{H_3} - C - C{H_3}} \\ 
      {\,\,\,||\,\,\,\,} \\ 
      {\,\,\,O\,\,\,\,} 
    \end{array}$
  • C
    $\begin{array}{*{20}{c}}
      {C{H_3} - C{H_2} - C - H} \\ 
      {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,} \\ 
      {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,} 
    \end{array}$
  • D
    $\begin{array}{*{20}{c}}
      {C{H_3} - CH - C{H_2}} \\ 
      {\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
      {\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,\,\,\,\,\,\,\,OH} 
    \end{array}$

Answer

Correct option: B.
$\begin{array}{*{20}{c}}
  {C{H_3} - C - C{H_3}} \\ 
  {\,\,\,||\,\,\,\,} \\ 
  {\,\,\,O\,\,\,\,} 
\end{array}$
b
The complete reaction is shown below.

$C{H_3} - C = CH\xrightarrow{{2HBr}}\mathop {\begin{array}{*{20}{c}}
  {Br} \\ 
  | \\ 
  {C{H_3} - C - C{H_3}} \\ 
  | \\ 
  {Br} 
\end{array}}\limits_{(A)} \xrightarrow{{{H_2}O}}$

$\begin{array}{*{20}{c}}
  {\,\,\,\,OH} \\ 
  | \\ 
  {C{H_3} - C - C{H_3}} \\ 
  | \\ 
  {\,\,\,\,\,OH} 
\end{array}\xrightarrow[{ - {H_2}O}]{}\mathop {\begin{array}{*{20}{c}}
  O \\ 
  {||} \\ 
  {C{H_3} - C - C{H_3}} 
\end{array}}\limits_{(B)} $

 

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