Major product
In the above reaction, $3.9\, g$ of benzene on nitration gives $4.92\, g$ of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is............. $\%$. (Round off to the Nearest Integer).
(Given atomic mass: $C : 12.0\, u , H : 1.0\, u$$O : 16.0\, u , N : 14.0\, u )$
$\underset{I}{\mathop{C{{H}_{3}}-C{{H}_{2}}-N{{H}_{2}}}}\,$
$\underset{II}{\mathop{{{(C{{H}_{3}}C{{H}_{2}})}_{2}}NH}}\,$
$\mathop {{{(C{H_3}C{H_2})}_3}N}\limits_{II} $
