C H_2 = C H_2 B r_2 / H_2 O A, In the above reaction the compound…

MCQ

$C{H_2} = C{H_2}\xrightarrow{{B{r_2}/{H_2}O}}A,$ In the above reaction the compound $A$ is

✓
Ethylene bromohydrin
B
$1, 2-$ dibromo ethane
C
Ethanol
D
None of these

✓

Answer

Correct option: A.

Ethylene bromohydrin

a
(a) $C{H_2} = C{H_2}\xrightarrow{{B{r_2},{H_2}O}}\mathop {\mathop {\mathop C\limits_| {H_2}}\limits_{Br\,\,\,\,} - \mathop {\mathop C\limits_| {H_2}}\limits_{OH\,\,\,\,} }\limits_{{\text{Ethylene bromohydrin}}} $
Hence compound $A$ is Ethylene bromohydrin.

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