MCQ
$CH_3 -CH_2 -CH=CH_2$ has hybridisation
- A$sp, sp, sp^2 , sp^2$
- B$sp^3 , sp^3 , sp^2 ,sp$
- ✓$sp^3 , sp^3 , sp^2 , sp^2$
- D$sp^3 , sp^2 , sp^2 , sp$
✓
Answer
Correct option: C.
$sp^3 , sp^3 , sp^2 , sp^2$
c
Given, $CH _3- CH _2- CH = CH _2$
Given, $CH _3- CH _2- CH = CH _2$
$S p^3$ hybridisation - single bond
$s p^2$ hybridisation - double bond
$s p$ hybridisation - triple bond
So, $CH _3- CH _2- CH = CH _2$ has hybridisation
$s p^3-s p^3-s p^2-s p^2$
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