MCQ
$(CH_3)_2C = C(CH_3)_2$ $\mathop {\xrightarrow{{{X_2}}}}\limits_{{H_2}O} A\mathop {\xrightarrow{{O{H^ - }}}}\limits_{} B$

  • B
    $\begin{array}{*{20}{c}}
      {{{(C{H_3})}_2}C - C{{(C{H_3})}_2}} \\ 
      {|\,\,\,\,\,\,\,\,|} \\ 
      {\,\,OH\,\,Cl} 
    \end{array}$
  • C
    $\begin{array}{*{20}{c}}
      {{{(C{H_3})}_2}C - C{{(C{H_3})}_2}} \\ 
      {|\,\,\,\,\,\,\,\,|} \\ 
      {\,\,OH\,\,OH} 
    \end{array}$
  • D
    None

Answer

Correct option: A.

a
The products $A$ and $B$ are as shown. In the first step, a molecule of $HOX$ is added across the $C = C$ double bond. In the second step, the epoxide is obtained.

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