MCQ
$C{H_3}C \equiv CC{H_3}\mathop {\xrightarrow{{(i){\text{ }}X}}}\limits_{(ii){H_2}O/Zn}$

$\begin{array}{*{20}{c}}
  {C{H_3} - C - C - C{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {O\,\,\,\,\,\,\,\,\,O} 
\end{array}$  $X$ in the above reaction is

  • A
    $HN{O_3}$
  • B
    ${O_2}$
  • ${O_3}$
  • D
    $KMn{O_4}$

Answer

Correct option: C.
${O_3}$
c
(c)$C{H_3} - C \equiv C - C{H_3}\mathop {\xrightarrow{{{\text{(i)}}\,{O_3}}}}\limits_{{\text{(ii)}}\,Zn/{H_2}O} C{H_3} - \mathop {\mathop C\limits_{||} }\limits_O  - \mathop {\mathop C\limits_{||} }\limits_O  - C{H_3}$

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