CH_3 CH=CH_2+HBr gives : - Vidyadip

MCQ

$\mathrm{CH}_3 \mathrm{CH}=\mathrm{CH}_2+\mathrm{HBr}$ gives :

✓
$ \mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2-\mathrm{Br} $
B
$ \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br} $
C
$ \mathrm{CH}_3 \mathrm{CH}(\mathrm{Br})-\mathrm{CH}_3 $
D
$ \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_3 $

✓

Answer

Correct option: A.

$ \mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2-\mathrm{Br} $

This is an example of addition reaction.
The double bond is broken and hydrogen and bromine are added to the given compound.
Bromine will add up on secondary carbon. $($Markovnikov's Rule$)\mathrm{CH}_3 \mathrm{CH}=\mathrm{CH}_2+\mathrm{HBr} \rightarrow \mathrm{CH}_3 \mathrm{CH}(\mathrm{Br})-\mathrm{CH}_3$.

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