MCQ
$C{H_3}COC{H_3}(g) \rightleftharpoons C{H_3} - C{H_3}(g) + CO(g)$ initial pressure of $CH_3COCH_3$ is $100\,mm$ . When equilibrium is set up mole fraction of $CO(g)$ is $\frac {1}{4}$ hence partial pressure of $CO$ is
  • A
    $\frac {50}{3}\,mm$
  • B
    $\frac {50}{12}\,mm$
  • C
    $\frac {25}{3}\,mm$
  • $\frac {100}{3}\,mm$

Answer

Correct option: D.
$\frac {100}{3}\,mm$
d
$\mathop {\mathop {C{H_3}COC{H_3}(g)}\limits_{100\,mm\,Hg} }\limits_{100 - x}  \rightleftharpoons \mathop {\mathop {{C_2}{H_6}(g)}\limits_0 }\limits_x  + \mathop {\mathop {CO(g)}\limits_0 }\limits_x $

$\begin{aligned} \frac{1}{4} &=x_{CO} \\ \frac{1}{4} &=\frac{x}{100+x} \\ \Rightarrow & 4 x=100+x \\ 3 x &=100 \end{aligned}$

$\mathrm{x}=\frac{100}{3}\,\mathrm{mm} \,\mathrm{Hg}$

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