MCQ
$C{H_3}MgI$ will give methane with
- A${C_2}{H_5}OH$
- B$C{H_3} - C{H_2} - N{H_2}$
- C$C{H_3} - CO - C{H_3}$
- ✓Both $(a)$ and $(b)$
$C{H_3}MgI + {C_2}{H_5}OH \to C{H_4} + {C_2}{H_5}OMgI$
Alkyl group of Grignard’s reagent is involved in the formation of alkane.
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$\mathrm{SO}_3, \mathrm{H}_2 \mathrm{SO}_3, \mathrm{SOCl}_2, \mathrm{SF}_4, \mathrm{BaSO}_4, \mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_7$