MCQ
$C{H_3}MgI$ will give methane with
- A${C_2}{H_5}OH$
- B$C{H_3} - C{H_2} - N{H_2}$
- C$C{H_3} - CO - C{H_3}$
- ✓Both $(a)$ and $(b)$
✓
Answer
Correct option: D.
Both $(a)$ and $(b)$
d
(d) $C{H_3}MgI + C{H_3} - C{H_2} - N{H_2} \to \,\,C{H_4} + C{H_3}C{H_2}NHMgI$
(d) $C{H_3}MgI + C{H_3} - C{H_2} - N{H_2} \to \,\,C{H_4} + C{H_3}C{H_2}NHMgI$
$C{H_3}MgI + {C_2}{H_5}OH \to C{H_4} + {C_2}{H_5}OMgI$
Alkyl group of Grignard’s reagent is involved in the formation of alkane.
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