$CHCl_3, CH_4$ અને $SF_4$ માંથી, કયા અણુઓ નિયમિત ભૂમિતિ ધરાવતા નથી?
Diffcult
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b As $CHCl _3$ has $Cl$ more electronegative than $H$ so it has not regular geometry Regular geometry of $CH _4$ is attributed to zero dipole moment $(\mu=0)$ and absence of lone pair on the carbon atom.
$SF _4$ has lone pair on $S$ so it will increase bond angle due to repulsion hence $CHCl _3$ and $SF _4$ has not regular geometry.
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