Question
Check the commutativity and associativity of the following binary operations:
'⊙' on Q defined by a ⊙ b = a2 + b2 for all a, b ∈ Q.

Answer

Commutativity: Let $\text{a, b}\in\text{Q}$ then,

a ⊙ b = a2 + b2

= b2 + a2

= b ⊙ a

Therefore,

a ⊙ b = b ⊙ a, $\forall\ \text{a, b}\in\text{Q}$

Thus, ⊙ is commuatative on Q.

Associativity: Let $\text{a, b, c}\in\text{Q.}$

a ⊙ (b ⊙ c) = a ⊙ (b2 + c2)

= ab2 + (b2 + c2)2

= ab2 + b4 + c4 + 2b2c2

(a ⊙ b) ⊙ c = (a2 + b2) ⊙ c

= (a2 + b2)2 + c2

= a4 + b4 + 2a2b2 + c2

Therefore,

$\text{a}\odot\text{b}\odot\text{c}\neq\text{a}\odot\text{b}\odot\text{c}$

Thus, ⊙ is not associative on Q.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free