MCQ
Chlorine can remove
- ✓$Br$ from $NaBr$ solution
- B$F$ from $NaF$ solution
- C$Cl$ from $NaCl$ solution
- D$F$ from $Ca{F_2}$ solution
✓
Answer
Correct option: A.
$Br$ from $NaBr$ solution
a
(a) $C{l_2} + 2NaBr\, \to \,2NaCl + B{r_2}$
(a) $C{l_2} + 2NaBr\, \to \,2NaCl + B{r_2}$
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