MCQ
Chlorine water on standing loses its colour and forms
- A$HCl$ only
- B$HCl$ and $HClO_2$
- ✓$HCl$ and $HOCl$
- D$HOCl$ and $HOCl_2$
$\begin{align}
+V\,\,\,\,\, \\
\,\,ClO_{3}^{-} \\
B.O.\,=\,1.67 \\
Hyb.\,\,of\,Cl\,:\,s{{p}^{3}} \\
\end{align}$ $\begin{align}
\,+VII\,\,\,\,\, \\
\,\,ClO_{4}^{-} \\
B.O.\,=\,1.75 \\
Hyb.\,\,of\,Cl\,:\,s{{p}^{3}} \\
\end{align}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$Cl_2 + 2Br^ - (aq.) \to 2Cl^-(aq.) + Br_2$
$Br_2$ gas thus formed is dissolved into solution of $Na_2CO_3$ and then pure $Br_2$ is obtained by treatment of the solution with