($\Delta {H_{eg}} = e^-$ gain enthalpy)
- A$S < Se < O$
- B$O < Se < S$
- C$S < O < Se$
- ✓$Se < S < O$
($\Delta {H_{eg}} = e^-$ gain enthalpy)
$\text{S}{{\text{O}}_{2}}+2{{\text{H}}_{2}}\text{O}\to {{\text{H}}_{2}}\text{S}{{\text{O}}_{4}}+\,\underset{nascent\,\,\,hydrogen}{\mathop{2H}}\,$
Thus, $\mathrm{SO}_{2}$ in presence of moisture is used as bleaching agent. This is due to the reducing nature of $\mathrm{SO}_{2}-$ For delicate articles
Coloured matter $+\mathrm{H} \longrightarrow$ Colourless matter
Similarly, $\mathrm{Cl}_{2}$ acts as bleaching agent in presence of moisture
$\text{C}{{\text{l}}_{2}}+{{\text{H}}_{2}}\text{O}\to 2\text{HCl}+[\text{O}]$
Coloured matter $+\,[O]\,\to $ Colourless matter
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for the above reaction at $298 K , K _{ c }$ is found to be $3.0 \times 10^{-59}$. If the concentration of $O _{2}$ at equilibrium is $0.040 M$ then concentration of $O _{3}$ in $M$ is ...... .

| $(A)$ | $OSF_2$ | $OSCl_2$ | $OSBr_2$ |
| $(B)$ | $SbCl_3$ | $SbBr_3$ | $SbI_3$ |
| $(C)$ | $PI_3$ | $AsI_3$ | $SbI_3$ |
${H_2}C = CH - CH = C{H_2}\xrightarrow[{0{\,^o}C}]{{HBr}}$ $\begin{array}{*{20}{c}}
{{H_2}C = CH - CH - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,}
\end{array}\xrightarrow{{ + 25{\,^o}C}}$ $\begin{array}{*{20}{c}}
{C{H_2}CH = CHC{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
These provide an example of $......1......$ control at low temperature and $......2......$ control at higher temperature