- A$[Cu(NH_3)_4]^{2+} < [Cu(en)_2]^{2+} < [Cu(trien)]^{2+}$
- ✓$[Fe(H_2O)_6]^{3+} < [Fe(NO_2)_6]^{3-} < [Fe(NH_3)_6]^{3+}$
- C$[Co(H_2O)_6]^{3+} < [Rh(H_2O)_6]^{3+} < [Ir(H_2O)_6]^{3+}$
- D$[Cr(NH_3)_6]^{1+} < [Cr(NH_3)_6]^{2+} < [Cr(NH_3)_6]^{3+}$
$(a)\, [Cu(NH_3)_4]^{2+} < [Cu(en)_2]^{2+} < [Cu(trien)]^{2+}$
Their formation entropy increases in the same order, because denticity of ligand increases
$(b)\, [Fe(H_2O)_6]^{3+} < [Fe(NO_2)_6]^{3-} < [Fe(NH_3)_6]^{3+}$
$NO_2^-$ is stronger ligand than $NH_3$
$(c)\, [Co(H_2O)_6]^{3+} < [Rh(H_2O)_6]^{3+} < [Ir(H_2O)_6]^{3+}$
$Z_{eff}$ value increases from $Co^{3+}$ to $Ir^{3+}$
$(d)\, [Cr(NH_3)_6]^{1+} < [Cr(NH_3)_6]^{2+} < [Cr(NH_3)_6]^{3+}$
Oxidation state of $Cr$ atom increases from $+ 1$ to $+3$.
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$Ca{C_2} + 2{H_2}O \to Ca{(OH)_2} + {C_2}{H_2}$
${C_2}{H_2} + {H_2} \to {C_2}{H_4}$
$n({C_2}{H_4}) \to {( - C{H_2} - C{H_2} - )_n}$
The amount of polyethylene obtained from $64.1\, kg$ $Ca{C_2}$ is......$kg$
${A_2}\left( g \right) + {B_2}\left( g \right) \rightleftharpoons 2AB\left( g \right)$
${\Delta _r}{G^o}$ and ${\Delta _r}{S^o}$ are $20\, kJ/mol$ and $-20\, JK^{-1}\, mol^{-1}$ respectively at $200\, K$.
If ${\Delta _r}{C_P}$ is $20\, JK^{-1}\, mol^{-1}$ then ${\Delta _r}{H^o}$ at $400\, K$ is.....$kJ/mol$
$(a)\,B{r_2}(l) \to B{r_2}(g)$
$(b)\,{H_2}O(s) \to {H_2}O(g)$
$(c)\,{N_2}\,\left[ {1\,atm,\,{{100}\,^o}C} \right] \to {N_2}\,\left[ {1\,atm,\,{{150}\,^o}C} \right]$
$(d)\,{N_2}\,(g) + 3{H_2}(g) \to 2N{H_3}(g)$
$(e)\,CaC{O_3}(s) \to CaO(s) + C{O_2}(g)$
Atomic no. : $Mn = 25,\,Fe = 26,\,Co = 27,\,Ni = 28$
${\text{Propanoic acid }}\xrightarrow{{SOC{l_2}}}X\xrightarrow{{N{H_3}}}Y\xrightarrow{{B{r_2} + KOH}}Z$
What is the compound $Z$