Question
Choose the correct answer from the given four options.
If a relation R on the set {1, 2, 3} be defined by R = {(1, 2)}, then R is:
  1. Reflexive.
  2. Transitive.
  3. Symmetric.
  4. None of these.

Answer

  1. Transitive.
Solution:
R on the set {1, 2, 3} be defined by R = {(1, 2)}
It is clear that R is transitive.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If the angle between the vectors $\overrightarrow{ a }$ and $\overrightarrow{ b }$ is $\frac{\pi}{4}$ and $|\vec{a} \times \vec{b}|=1$, then $\vec{a} \cdot \vec{b}$ is equal to
If the three points A(1, 6), B(3, −4) and C(x, y) are collinear, then the equation satisfying by x and y is:
For two events $A$ and $B$, if $P(A)=0.4, P(B)=0.8$ and $P(B / A)=0.6$, then $P(A \cup B)$ is
If $A$ and $B$ are matrices of the same order, then $AB^T - BA^T$ is $a:$
$\int_{0}^{\frac{\pi^2}{4}}\frac{\sin\sqrt{\text{y}}}{\sqrt{\text{y}}}.$
  1. $1$
  2. $2$
  3. $\frac{\pi}{4}$
  4. $\frac{\pi^2}{8}$
If $\text{x }\epsilon\Big(-\frac{\pi}{2},\frac{\pi}{2}\Big),$ then the value of $\tan^{-1}\Big(\frac{\tan\text{x}}{4}\Big)+\tan^{-1}\Big(\frac{3\sin2\text{x}}{5+3\cos2\text{x}}\Big)$ is:
  1. $\frac{\text{x}}{2}$
  2. 2x
  3. 3x
  4. x
The vector equation r = i − 2j − k + t(6j − k) represents a straight line passing through the points:
  1. (0, 6, −1) and (1, −2, −1)
  2. (0, 6, −1) and (−1, −4, −2)
  3. (1, −2, −1) and (1, 4, −2)
  4. (1, −2, −1) and (0, −6, 1)
By graphical method, the solution of linear programming problem
Maximize $Z = 3x_1 + 5x_2$
Subject to
$3x_1 + 2x_2 \leq 18$
$x_1 \leq 4$
$x_2 \leq 6$
$x_1 \geq 0, x_2 \geq 0,$ is:
If $\overline{\text{a}},\overline{\text{b}},\overline{\text{c}}$ are unit vectors such that $\overline{\text{a}}+\overline{\text{b}}+\overline{\text{c}}+\overline{\text{c.a}}=$
  1. $\frac{3}{2}$
  2. $-\frac{3}{2}$
  3. $\frac{1}{2}$
  4. $-\frac{1}{2}$
The direction ratios of the line of intersection of the planes 3x + 2y - z = 5 and x - y + 2z = 3 are:
  1. 3, 2, -1
  2. -3, 7, 5
  3. 1, -1, 2
  4. -11, 4, -5