MCQ
Choose the correct answer from the given four options. Let $f:[2, \infty) \rightarrow R$ be the function defined by $f(x)=x^2-4 x+ 5$, then the range of $f$ is:
  • A
    $\text{R}$
  • $[1,\infty)$
  • C
    $[4,\infty)$
  • D
    $[5,\infty)$

Answer

Correct option: B.
$[1,\infty)$
Given that, $\text{f}(\text{x})=\text{x}^2-4\text{x}+5,$
Let $\text{y}=\text{x}^2-4\text{x}+5$
$\Rightarrow\ \text{y}=\text{x}^2-4\text{x}+4+1$
$=(\text{x}-2)^2+1$
$\Rightarrow\ (\text{x}-2)^2=\text{y}-1$
$\Rightarrow\ \text{x}-2=\sqrt{\text{y}-1}$
$\Rightarrow\ \text{x}=2+\sqrt{\text{y}-1}$
$\therefore\ \text{y}-1\geq0,\ \text{y}\geq1$
Range $=[1,\infty)$

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