MCQ
Choose the correct answer.
If – 3x + 17 < – 13, then:
  • A
    $\text{x}\in(10, \infty)$ 
  • B
    $\text{x}\in[10, \infty)$ 
  • C
    $\text{x}\in(-\infty\text{j},10]$ 
  • D
    $\text{x}\in[-10, 10)$

Answer

  1. $\text{x}\in(10, \infty)$

Solution:

Given that - 3x + 17 < - 13

⇒ - 3x < - 17 - 13

⇒ -3x < - 30

⇒ 3x > 30

⇒ x > 10

$\Rightarrow\text{x}\in(10, \infty)$

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