MCQ
Choose the correct answers:
Range of $\text{f(x)}=\frac{1}{1-2\cos\text{x}}$ is.
  • A
    $\Big[\frac{1}{3}, 1\Big]$
  • B
    $\Big[-1, \frac{1}{3}\Big]$
  • $(-\infty, -1]\cup\Big[\frac{1}{3},\infty\Big)$
  • D
    $\Big[-\frac{1}{3}, 1\Big]$

Answer

Correct option: C.
$(-\infty, -1]\cup\Big[\frac{1}{3},\infty\Big)$
We know that, $-1\leq-\cos\text{x}\leq1$
$\Rightarrow-1\leq-\cos\text{x}\leq1$
$\Rightarrow-2\leq-2\cos\text{x}\leq2$
$\Rightarrow-1\leq-2\cos\text{x}\leq3$
Now $\text{f(x)}=\frac{1}{1-2\cos\text{x}}$ is defined if
$-1\leq-2\cos\text{x}\leq0$ or $0<1-2\cos\text{x}\leq3$
$\Rightarrow-1\geq\frac{1}{1-2\cos\text{x}}>-\infty$ or $\infty>\frac{1}{1-2\cos\text{x}}\geq\frac{1}{3}$
$\Rightarrow\frac{1}{1-2\cos\text{x}}\in(-\infty, -1]\cup\Big[\frac{1}{3},\infty\Big)$

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