- A$2, 3-$ dimethyl- $4-$ hexyne
- ✓$4,5-$ dimethyl- $2-$ hexyne
- C$5-$ propyl- $2-$ pentyne
- D$2-$ propyl- $3-$ pentyne
$4, 5-$ di methyl -$2-$ hexyne
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$NO_2^ + \to N{O_2} \to NO_2^ - $
$\Delta_f G^0[\mathrm{C}(\text { graphite })]=0 \mathrm{kJmol}^{-1}$
$\Delta_f G^0[\mathrm{C}(\text { diamond })]=2.9 \mathrm{kJmol}^{-1}$
The standard state means that the pressure should be $1$ bar, and substance should be pure at a given temperature. The conversion of graphite [C(graphite)] to diamond [C(diamond)] reduces its volume by $2 \times 10^{-6} \mathrm{~m}^3 \mathrm{~mol}^{-1}$. If $\mathrm{C}$ (graphite) is converted to $\mathrm{C}$ (diamond) isothermally at $\mathrm{T}=298 \mathrm{~K}$, the pressure at which $C$ (graphite) is in equilibrium with C(diamond), is
[Useful information: $1 \mathrm{~J}=1 \mathrm{~kg} \mathrm{~m}^2 \mathrm{~s}^{-2} ; 1 \mathrm{~Pa}=1 \mathrm{~kg} \mathrm{~m}^{-1} \mathrm{~s}^{-2} ; 1 \mathrm{bar}=10^5 \mathrm{~Pa}$ ]
$56\ g$ of nitrogen and $8\ g$ of hydrogen gas are heated in a closed vessel. At equilibrium, $34\ g$ of ammonia are present. The equilibrium number of moles of nitrogen, hydrogen and ammonia are respectively