MCQ
The number of possible isomers for disubstituted borazine, $\mathrm{B}_3 \mathrm{N}_3 \mathrm{H}_4 \mathrm{X}_2$​ is:
  • A
    $3$
  • $4$
  • C
    $6$
  • D
    $2$

Answer

Correct option: B.
$4$
The number of possible isomers of distributed borazine is $4$ because of $4$ reactive hydrogen ions.

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