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$C{H_3}C{H_2}C{H_2}Br$ $\xrightarrow{{KOH(alc.)}}\,(A)\,\xrightarrow{{HBr}}(B)\,$ $\xrightarrow{{KOH(aq.)}}(C)$ The product $(C)$ is

$\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - CH - C{H_3}\xrightarrow{{C{H_3}{O^\Theta }}}X} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{F\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ product
The alkene formed in major amount
$\begin{array}{*{20}{c}}
{C{H_3} - C = CH - {C_6}{H_5}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow{{HBr\,/\,Peroxide}}'A'$
$\begin{array}{*{20}{c}}
{C{H_3} - C = CH - {C_6}{H_5}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow[{HBr}]{}'B'$
