-I effect of Cl disperses -ve charge on O atom to produce more stable anion
\(\mathrm{ClCH}_2 \mathrm{CH}_2 \mathrm{OH}\) is stronger acid than \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}\) due to -1 effect of Cl
પ્રકિયા $- (2): CH_3 -CH = CH -CH_3 \xrightarrow{KMn{{O}_{4}}/NaI{{O}_{4}}}(C)$ $2$ મોલ
નીપજ $(B)$ અને $(C)$ શું હશે ?