MCQ
Collin’s reagent is
- A$MN{O_2}/HCl$
- B$MN{O_4}/{C_5}{H_5}N$
- C${K_2}C{r_2}{O_7}/{H_2}S{O_4}$
- ✓$C{r_2}{O_3}/2{C_5}{H_5}N$
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$M{n_{(S)}}|Mn_{(aq)}^{ + 2}(0.4\,M)||Sn_{(aq)}^{ + 2}(0.04\,M)|S{n_{(S)}}$,
Calculate free energy change $(\Delta G)$ at $298\,K$ .
Given :$E_{M{n^{ + 2}}|Mn}^o = \, - \,1.18\,V\,;\,E_{S{n^{ + 2}}|Sn}^o\, = \, - \,0.14\,volt$
$\frac{{2.303\,RT}}{F} = 0.06$
