MCQ
The outer electronic structure of lawrencium (atomic number $103$) is
- A$Rn\,\, 5f^{13} \,7s^2 \,7p^2$
- B$Rn\, \,5f^{13}6\,d^1 \,7s^1\, 7p^2$
- C$Rn\,\, 5f^{14}\, 7s^1 \,7p^2$
- ✓$Rn\, \,5f^{14} \,6d^1\, 7s^2$
Lawrencium is an Actinide present in $5 f$ series of $f$-Block elements.
The outermost configuration $=\left[Rn\right]\, 5 f^{14} \,7s^2 \,7 p^1$
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$A$ and $B$ are :
$(I)$ They have high melting points, higher than those of pure metals
$(II)$ They are very hard
$(III)$ They retain metallic conductivity
$(IV)$ They are chemically more reactive than the pure metals


$Ag\left( s \right)/A{g^ \oplus }||C{u^{2 + }}/Cu\left( s \right)$
$A{g^ \oplus } + {e^ - } \to Ag\,;\,{E^o} = x$
$C{u^{2 + }} + 2{e^ - } \to Cu\,;\,{E^o} = y$
$E^o_{cell}$ is