Combustion of glucose takes place according to the equation, C_6 … - Vidyadip

MCQ

Combustion of glucose takes place according to the equation, ${C_6}{H_{12}}{O_6} + 6{O_2} \to 6C{O_2} + 6{H_2}O$,$\Delta H = - 72\,kcal$. How much energy will be required for the production of $1.6 \,g$ of glucose......$kcal$. (Molecular mass of glucose $= 180 \,g$)

A
$0.064$
✓
$0.64$
C
$6.4$
D
$64$

✓

Answer

Correct option: B.

$0.64$

(b) $\Delta H\,per\,1.6\,g = \frac{{72 \times 1.6}}{{180}} = 0.64\,kcal$.

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