Gujarat BoardEnglish MediumSTD 8MATHSAlgebraic Expressions, Identities and Factorisation1 Mark
MCQ
Common factor of $17abc, 34ab^2, 51a^2b$ is:
A
$17abc$
✓
$17ab$
C
$17ac$
D
$17a^2b^2c$
✓
Answer
Correct option: B.
$17ab$
Given, $17??? = 17 \times a \times b\times c\ 34ab^2$
$= 2 \times 17 \times a \times b \times b\ 51a\ 2b $
$= 3 \times 17 \times a \times a \times a$
Now, collecting the common factors,
we get $17 \times a \times b $
$= 17ab$
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