Question
- Compare and classify the population densities shown in the squares ‘a’ and
‘b’ representing 1 sq.km of area. - If in figure B, one sign = 100, then what will be the sex ratio?
(a)
(b)
(a)
(b)
The density of population in figure (a) is less than the density of population in figure (b). Thus, figure (a) shows sparse population while figure (b) shows dense population.
Given that, one sign = 100 persons.
Since, there are 10 female signs, there are:
10 × 100 = 1000 females
Since, there are 8 male signs, there are:
8 × 100 = 800 males
If number of males = 1000,
then number of females =?
$\therefore$ Sex ratio $=1000 \times \frac{1000}{800}=1250$
∴ The sex ratio in this case is favourable.
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