MCQ
Complete combustion of $C{H_4}$ gives
- ✓$C{O_2} + {H_2}O$
- B$C{O_2} + {H_2}$
- C$COC{l_2}$
- D$CO + C{O_2} + {H_2}O$
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if $T_1 < T_2$ then $X$ and $Y$ respectively are

$(R= 8.314\,\,JK^{-1}\,\,mol^{-1};\,\,ln\,2 = 0.693;\,\,ln\,3 = 1.098)$